AbraCalc

Work Done by 50 N at 30° Over 5 m

A 50 N force applied at 30° over 5 m does approximately 216.5 joules of work.

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  1. Enter force, distance and angle between f and d in the fields above.
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  3. Read your work done and the full breakdown beneath it.

Find the work done when a 50 N force is applied at 30° to the direction of motion over 5 metres.

Frequently asked questions

What if the force is applied at an angle?
Only the component along the direction of motion does work. A force at 60° contributes cos(60°) = 0.5 of its magnitude.
How is work related to energy?
The work-energy theorem states that net work done on an object equals its change in kinetic energy: W_net = ΔKE.